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    CLASS 7 • MATHEMATICS • PART-II • CHAPTER 6

    Constructions and Tilings

    Use a ruler and compass to build precise geometric figures — then discover how shapes cover regions without gaps or overlaps.

    In this chapter, you will construct perpendicular bisectors, angles, parallel lines, arches and hexagons, then explore tangrams, grid tilings, symmetry and patterns that fill the plane.

    Interactive Geometry Visualizer
    XYABO (90°)
    💡 Core Philosophy: Constructions use only an unmarked straightedge and a compass. Every construction step is mathematically justified by triangle congruence (SSS, SAS)!

    By the End of This Chapter, You Will Be Able To:

    Construct the perpendicular bisector of a line segment using an unmarked ruler and compass
    Explain why the perpendicular bisector works using SSS and SAS triangle congruence
    Construct a 90° angle at a given point on a line with a single pair of arcs
    Appreciate the ancient Indian Śulba-Sūtras rope construction method
    Bisect any given angle and construct 45°
    Copy any given angle to another vertex using chord transfer and SSS congruence
    Construct parallel lines through an external point using corresponding angles
    Construct architectural trefoil arches and pointed arches
    Construct a 60° angle using an equilateral triangle, and bisect it to 30° and 15°
    Construct regular hexagons from six congruent equilateral triangles around a point
    Construct a 6-pointed star and identify its order-6 rotational symmetry
    Solve 7-piece Chinese Tangram geometric dissection puzzles
    Define tiling (tessellation) as covering a region without gaps or overlaps
    Determine domino tileability of m × n rectangular grids using area parity arguments
    Master the black-and-white checkerboard proof to prove tiling impossibility
    Identify which regular polygons tile the entire plane (triangles, squares, hexagons)
    Explain why regular pentagons cannot tile the plane using 360° vertex angle sums
    Explore M.C. Escher tilings and discover why honeybees construct hexagonal cells

    The Classical Construction Toolkit

    In classical Euclidean geometry and the NCERT curriculum, constructions are executed using only two fundamental instruments without measuring numbers:

    Unmarked Ruler

    Draws straight line segments of arbitrary length connecting two given points.

    Compass

    Draws circles, circular arcs, and transfers precise lengths without numerical measurement.

    Pencil & Pointer

    Marks distinct points of intersection between lines, rays, and arcs.

    ⚠️ Important Rule: A marked ruler (centimeter scale) is only used when drawing a line of a specific assigned length. A protractor is NOT permitted for constructing angles; all angles (90°, 45°, 60°, 30°, 15°) must be constructed with compass arcs!
    Section 6.1

    6.1 Geometric Constructions

    Eyes, Perpendicular Bisectors, Congruence Proof, Locus, 90°, Śulba-Sūtras, Angles, Arches & Hexagons

    The ‘Eyes’ Construction (Textbook Pages 136–137)

    How circular arcs drawn from centers A and B produce a symmetrical eye shape

    XYAB
    Key Condition for Symmetry:

    For the upper and lower arcs to match symmetrically along line XY, centres A and B must satisfy:

    AX = AY = BX = BY

    Therefore, A is equidistant from X and Y, and B is equidistant from X and Y. Connecting A and B produces the perpendicular bisector of XY!

    Perpendicular Bisector Construction & Mathematical Proof

    Follow the 3-step classical construction and inspect why ΔAOX ≅ ΔAOY

    XYABO90°

    Current Step 3: Draw the straight line AB. Line AB passes through the midpoint O of XY and forms a 90° right angle with XY, bisecting it perpendicularly.

    The Equal-Distance Locus Principle

    Drag point P horizontally and vertically. Discover that PX = PY happens if and only if P lies exactly on the perpendicular bisector line (x = 200)!

    Distance PX135 px
    Distance PY135 px
    StatusPX = PY ✓ (On Bisector!)

    Construction of a 90° Angle at a Given Point (Page 141)

    Given point O on a line: mark X and Y equidistant from O ($OX = OY$). Then O is the midpoint of segment XY. Constructing arcs above O gives point A, producing ray OA $\perp$ line with only one pair of arcs!

    Step 3: Join OA. Ray OA forms an exact 90° right angle at O! No arcs needed below because point O is already on the perpendicular bisector.

    Ancient Construction Methods — The Śulba-Sūtras

    Kātyāyana-Śulbasūtra 1.2

    Ancient Indian geometric texts of the Vedic period, known as Śulba-Sūtras ('rules of the cord'), were used for constructing sacrificial fire altars with exact geometric proportions. Instead of a modern compass, ancient geometers used a rope (rajju) fastened to pegs (śanku) at endpoints X and Y. Folding the rope in half marked its midpoint. Stretching the midpoint taut above XY gave point A, and stretching it below gave point B. Line AB is the exact perpendicular bisector!

    Rope Midpoint Simulation:

    Angle Bisection Lab & 45° Angle (Pages 143–145)

    Cut arcs OA = OB on arms, then intersect arcs from A and B at C

    YOXABC (Bisector)35.0°
    SSS Congruence Justification: $OA = OB$ (equal radii), $AC = BC$ (equal arc radii), and $OC$ is common. Thus $\Delta OBC \cong \Delta OAC$, so $\angle BOC = \angle AOC = \frac12 \angle AOB$!

    Gap Angle Around a Point (Textbook Page 152)

    Angles meeting at point O: 40°, 60°, 50°, 30°, 40°, and 90°. What is the remaining gap angle, and will a 70° angle fit?

    Sum of given angles = 40° + 60° + 50° + 30° + 40° + 90° = 310°
    Complete angle around a point = 360°
    Remaining Gap Angle = 360° − 310° = 50°
    ❌ Will a 70° angle fit? No! The gap is only 50°. An angle of 70° exceeds the gap by 20° and will overlap adjacent rays.

    Constructing 60° Angles & Regular Hexagons

    Six equilateral triangles fitting around a central point ($6 \times 60^\circ = 360^\circ$)

    Side = 4 cm
    How to Construct a 60° Angle:
    1. Draw segment AX.
    2. With centre A and radius r, draw an arc cutting AX at B.
    3. With centre B and the exact same radius r, cut the first arc at C.
    4. Join AC. Since $AB = BC = AC = r$, $\Delta ABC$ is equilateral!
    5. Therefore, $\angle CAX = 60^\circ$.
    Bisection Family:
    60° (Equilateral triangle)
    ↓ Bisect
    30°
    ↓ Bisect
    15°
    Section 6.2

    6.2 Tiling

    Tangrams, 2×1 Domino Tilings, Area Parity, Checkerboard Impossibility Proofs & Plane Tessellations

    What is Tiling? (No Gaps, No Overlaps)

    Tiling (or tessellation) means covering a region or the flat plane using a set of shapes such that there are zero gaps (no uncovered holes) and zero overlaps (no shapes on top of each other).

    ✓ Valid Tiling

    Shapes meet edge-to-edge seamlessly.

    ✗ Gap

    Uncovered empty space left behind.

    ✗ Overlap

    Shapes crossing over each other's boundaries.

    Chinese Tangram Lab (7 Geometric Pieces)

    7 Pieces from a Single Square:
    • 2 Large Triangles (Pieces A & B)
    • 1 Medium Triangle (Piece D)
    • 2 Small Triangles (Pieces C & E)
    • 1 Square (Piece G)
    • 1 Parallelogram (Piece F)

    All 7 pieces combine without overlapping to form figures such as arrows, birds, running persons, and letters!

    Domino Tiling of m × n Grids: The Area Parity Rule

    Can an m × n grid of unit squares be tiled using 2 × 1 domino tiles?

    4 × 6 GridTileable
    Total Squares = 24 (Even)

    Both dimensions are even. Each column of 4 squares can be covered by 2 vertical dominoes.

    4 × 7 GridTileable
    Total Squares = 28 (Even)

    One dimension (4) is even. Each column of 4 squares can be covered by 2 vertical dominoes.

    5 × 7 GridImpossible
    Total Squares = 35 (Odd)

    Total area is 35 (odd). Each 2×1 domino covers exactly 2 squares. An odd number of squares can never be covered by dominoes without a gap!

    Test Any m × n Grid:
    4 × 6 = 24 squares (Even Area) → Tileable with 2×1 dominoes! (At least one dimension is even)

    The Checkerboard Colouring Proof (Textbook Pages 158–160)

    Click any square in the 5 × 3 grid to remove it, and inspect the Black vs White count

    Fig. 6.13 & 6.14

    A 5 × 3 grid has 15 squares. When one square is removed, 14 squares remain (an even number!). Is it automatically tileable? Click a square below to remove it and find out:

    Click a square to remove:
    White Squares remaining:7
    Black Squares remaining:7
    Total remaining squares:14 (Even)
    ✓ Equal Counts (7 White, 7 Black)

    Both colors have 7 squares! Equal counts remove the color obstruction, enabling a valid domino tiling.

    The Power of Proof vs. Failed Search (Textbook Page 160):

    If you try for hours and fail to find a tiling, that only means you haven't found one yet. But the black-and-white coloring argument is a mathematical proof of impossibility: it proves that no possible arrangement can ever exist!

    Tiling the Entire Plane: The 360° Vertex Sum Condition

    Which regular polygons can tile a flat surface seamlessly without gaps or overlaps?

    Regular Hexagon (6 Sides)Tiles the Plane ✓
    Interior Angle: 120°
    At a Vertex: 360° ÷ 120° = 3.00

    3 × 120° = 360°. Exactly 3 regular hexagons meet at every vertex. Used by bees in honeycombs to maximize area with minimal perimeter!

    Did You Know? (Page 162)

    In 2023, mathematicians discovered a 13-sided polygon nicknamed ‘the hat’—an aperiodic monotile that tiles the entire plane without ever repeating periodically!

    Nature's Honeycomb:

    Bees and wasps construct hexagonal cells because regular hexagons have the lowest perimeter-to-area ratio among plane-tiling polygons, maximizing honey storage with minimum wax!

    Practice Zone (40 Graded Questions)

    Progress through Foundation, Application, Challenge, and Master tiers

    FoundationSection 6.1
    Q1

    What is the mathematical definition of 'bisection' of a line segment?

    FoundationSection 6.1
    Q2

    When constructing the perpendicular bisector of segment XY with compass centres at X and Y, what must be true about the radius chosen?

    FoundationSection 6.1
    Q3

    What is the measure of the angle formed between a line segment and its perpendicular bisector?

    FoundationSection 6.1
    Q4

    How can a 45° angle be constructed using only a ruler and compass?

    FoundationSection 6.1
    Q5

    Which triangle congruence condition justifies that the angle bisector ray OC divides ∠XOY into two equal angles?

    FoundationSection 6.1
    Q6

    What type of triangle is formed when constructing a 60° angle at vertex A with equal arc radii AB = BC = AC?

    FoundationSection 6.2
    Q7

    What is the definition of 'tiling' (or tessellation) of a region?

    FoundationSection 6.2
    Q8

    Can a 5 × 7 rectangular grid of unit squares be tiled using 2 × 1 domino tiles?

    FoundationSection 6.2
    Q9

    How many pieces make up a traditional Chinese Tangram puzzle?

    FoundationSection 6.1
    Q10

    In the ancient Indian Śulba-Sūtras, what practical tool was used as both a compass and a straightedge?

    ApplicationSection 6.1
    Q11

    When constructing the perpendicular bisector of segment XY, is it necessary that the radius of the arcs drawn above XY equals the radius of the arcs drawn below XY?

    ApplicationSection 6.1
    Q12

    To construct a 90° angle at a given point O on a line, why is only ONE pair of intersecting arcs needed instead of two?

    ApplicationSection 6.1
    Q13

    How can an angle of 30° be constructed using a ruler and compass?

    ApplicationSection 6.1
    Q14

    How can an angle of 15° be constructed?

    ApplicationSection 6.1
    Q15

    In the textbook angle-sum puzzle (Page 152), the angles around point O are 40°, 60°, 50°, 30°, 40°, and 90°. Will a 70° angle fit into the remaining gap?

    ApplicationSection 6.1
    Q16

    Why do six congruent equilateral triangles arranged around a common vertex form a regular hexagon?

    ApplicationSection 6.1
    Q17

    To construct a line parallel to line m through an external point B, which geometric principle is used?

    ApplicationSection 6.2
    Q18

    A 4 × 7 grid has 28 unit squares. Can it be tiled using 2 × 1 dominoes?

    ApplicationSection 6.2
    Q19

    In a checkerboard (black-and-white) colouring of a grid, why does every 2 × 1 domino cover exactly 1 black and 1 white square?

    ApplicationSection 6.2
    Q20

    A 5 × 3 grid has 15 squares. If one corner square is removed, 14 squares remain. When colored as a checkerboard, there are 8 white squares and 6 black squares. Can the remaining 14 squares be tiled with 2 × 1 dominoes?

    ChallengeSection 6.1
    Q21

    What is the locus of all points in a plane that are equidistant from two given points X and Y?

    ChallengeSection 6.1
    Q22

    Can an angle of 65.5° be constructed using only an unmarked ruler and compass?

    ChallengeSection 6.1
    Q23

    In the 6-pointed star construction (Textbook Page 154), six triangles are built on the edges of a regular hexagon. Are these six outer triangles equilateral?

    ChallengeSection 6.2
    Q24

    If a region has an EQUAL number of black and white squares on a checkerboard, does this GUARANTEE that it can be tiled with 2 × 1 dominoes?

    ChallengeSection 6.2
    Q25

    Why can regular hexagons tile the entire plane seamlessly, while regular octagons (8-sided) cannot tile the plane by themselves?

    ChallengeSection 6.1
    Q26

    How do you construct a perpendicular to a line l through an external point P not lying on l?

    ChallengeSection 6.1
    Q27

    What is the order of rotational symmetry of the 6-pointed star shown on textbook page 154?

    ChallengeSection 6.2
    Q28

    What general rule determines whether an m × n rectangular grid of unit squares can be tiled with 2 × 1 dominoes?

    ChallengeSection 6.1
    Q29

    In the trefoil arch construction (page 149), what geometric symmetry condition must the support lines AB and CD satisfy with the base segment AD?

    ChallengeSection 6.2
    Q30

    Why do honeybees build honeycomb cells in regular hexagonal prisms rather than square or triangular prisms?

    MasterSection 6.1
    Q31

    In the 8-petalled flower construction, what is the exact angle between any two consecutive supporting rays emanating from the center?

    MasterSection 6.1
    Q32

    A line segment AB has length 10 cm. How many lines in the plane can be perpendicular bisectors of AB?

    MasterSection 6.2
    Q33

    In 2023, mathematicians discovered a single non-periodic shape that can tile the entire plane without ever repeating periodically. What nickname was given to this 'einstein' tile?

    MasterSection 6.1
    Q34

    If point P lies on the perpendicular bisector of segment XY, which of the following is strictly TRUE?

    MasterSection 6.2
    Q35

    Consider an 8 × 8 chessboard with two diagonally opposite corner squares removed (leaving 62 squares). Can this board be tiled with 31 dominoes of size 2 × 1?

    MasterSection 6.1
    Q36

    What is the interior angle of a regular polygon with n sides?

    MasterSection 6.2
    Q37

    Which Dutch graphic artist (1898–1972) is world-famous for creating mathematical tilings featuring interlocking birds, fish, and reptiles?

    MasterSection 6.1
    Q38

    When bisecting an angle ∠XOY, if the arcs of equal radius from A and B are drawn on the opposite side of O (away from the angle opening), does the resulting line OC still bisect ∠XOY?

    MasterSection 6.2
    Q39

    Which of the following sets contains ALL regular polygons that can tile the Euclidean plane on their own?

    MasterSection 6.1
    Q40

    In a regular hexagon with side length s, what is the distance between two opposite vertices (e.g. AD in Fig. 6.12)?

    Final Chapter Assessment (20 Questions)

    Comprehensive test of constructions, triangle congruence, angles, dominoes, and tessellations

    Q1. What geometric figure is constructed by finding the intersection of arcs of equal radius from two endpoints X and Y?
    Q2. Why does the perpendicular bisector proof use both ΔABX ≅ ΔABY and ΔAOX ≅ ΔAOY?
    Q3. When constructing a 90° angle at point O on a line, why do we first mark points X and Y equidistant from O?
    Q4. In the Śulba-Sūtra rope method, what guarantees that the pulled midpoint A lies on the perpendicular bisector?
    Q5. How do you bisect an angle ∠XOY using a compass?
    Q6. What is the angle between adjacent rays in an 8-petalled flower design covering 360°?
    Q7. Which triangle congruence criterion is used to copy an angle from one vertex to another using ruler and compass?
    Q8. How are parallel lines constructed through an external point B using an unmarked ruler and compass?
    Q9. What is the measure of each interior angle of an equilateral triangle?
    Q10. How many equilateral triangles meeting at a single vertex are required to form a complete regular hexagon?
    Q11. In the textbook angle puzzle, angles 40°, 60°, 50°, 30°, 40°, and 90° meet at a point. What is the remaining gap angle?
    Q12. What is the interior angle of a regular hexagon?
    Q13. What is the rotational symmetry order of a regular 6-pointed star?
    Q14. Why can a 5 × 7 grid NEVER be tiled using 2 × 1 dominoes?
    Q15. What does the black-and-white checkerboard proof establish about domino tilings?
    Q16. Which three regular polygons can tile the entire flat Euclidean plane on their own?
    Q17. Why CANNOT regular pentagons tile the flat plane by themselves?
    Q18. What architectural feature in the Red Fort (Diwan-i-Aam) and Central Park NYC is constructed using symmetrical supporting lines and circular arcs?
    Q19. If a 5 × 3 grid (15 squares) has one corner square removed, how many black and white squares are left in an alternating checkerboard pattern?
    Q20. What is the primary difference between failing to find a tiling and proving that no tiling exists?

    Quick Revision Flashcards

    Card 1 of 10
    Question (Click to Flip)

    What is bisection?

    12 Common Geometric & Tiling Misconceptions to Avoid

    ✗
    Believing that equal counts of black and white squares guarantee a region can be tiled.
    Equal counts ($B = W$) is a necessary condition, but not a sufficient condition. Isolated or bottlenecked squares can still prevent tiling.
    A board with two isolated white squares on one end and two isolated black squares on the other has $B = W = 2$, but cannot be tiled by dominoes.
    ✗
    Assuming that all regular polygons can tile the flat plane.
    Only three regular polygons tile the Euclidean plane on their own: equilateral triangles, squares, and regular hexagons.
    Regular pentagons (interior angle 108°) cannot tile the plane because $3 \times 108^\circ = 324^\circ \ne 360^\circ$.
    ✗
    Using a compass radius smaller than half the segment length when constructing a perpendicular bisector.
    The radius must be strictly greater than $\frac{1}{2} XY$; otherwise the circular arcs will not intersect.
    If $XY = 8\text{ cm}$ and radius is $3\text{ cm}$, the arcs from X and Y remain separated by a $2\text{ cm}$ gap.
    ✗
    Thinking a marked ruler with centimeter gradations is required for classical geometric constructions.
    Classical Euclidean constructions use only an UNMARKED straightedge (to connect points) and a compass (to draw arcs and transfer distances).
    Finding a midpoint by measuring with a ruler is an empirical approximation; constructing the perpendicular bisector is exact.
    ✗
    Confusing perpendicular lines with parallel lines.
    Perpendicular lines intersect at a 90° right angle; parallel lines lie in the same plane and never intersect.
    $AB \perp XY$ means $90^\circ$; $m \parallel n$ means constant distance apart.
    ✗
    Believing you must draw arcs both above and below the segment to construct a perpendicular bisector.
    Any two distinct points equidistant from endpoints define the bisector. Both points can lie on the same side if different radii are used!
    Constructing point A with radius $5\text{ cm}$ and point C with radius $7\text{ cm}$ on the same side yields line AC, which is the bisector.
    ✗
    Thinking an angle can be bisected by measuring the chord with a ruler and dividing by two.
    Compass arc intersections mathematically produce congruent triangles (SSS), ensuring angle equality without measurement error.
    Bisecting $\angle XOY$ by constructing $OA = OB$ and $AC = BC$ guarantees $\Delta OAC \cong \Delta OBC$.
    ✗
    Assuming a 2×1 domino can only be placed horizontally.
    Dominoes can be placed in any orthogonal orientation: horizontal ($1 \times 2$) or vertical ($2 \times 1$).
    A $4 \times 7$ grid is tiled by orienting all dominoes vertically in each column of length 4.
    ✗
    Claiming that honeybees choose hexagons because they understand geometry.
    Hexagonal honeycombs are an evolutionary and physical equilibrium: hexagons maximize storage volume while minimizing wax perimeter.
    Hexagonal structures emerge naturally under surface tension and evolutionary selection pressure.
    ✗
    Thinking that an odd number of unit squares can be tiled with 2×1 dominoes if pieces are allowed to overhang.
    Tiling strictly forbids gaps, overlaps, and overhangs beyond the boundary of the region.
    A $5 \times 7 = 35$ grid cannot be tiled by dominoes under any circumstances.
    ✗
    Assuming the compass measures distances numerically.
    A compass captures and transfers lengths as rigid distances, without assigning a numerical number or unit to them.
    Copying chord $BC$ to arc point $Z$ transfers the distance $BC = YZ$ purely geometrically.
    ✗
    Thinking a 60° angle requires a protractor.
    A 60° angle is constructed exactly with an unmarked ruler and compass by creating an equilateral triangle.
    Arc of radius $r$ from A cutting line at B, then arc of radius $r$ from B cutting the first arc at C gives $\angle CAB = 60^\circ$.

    Key Geometric & Tiling Terms

    Bisection

    The division of a line segment, angle, or geometric quantity into two congruent (identical) halves.

    Perpendicular Bisector

    A straight line that bisects a segment at its midpoint at an angle of exactly 90°.

    AB ⟂ XY and OX = OY
    Locus (Equal-Distance Property)

    The set of all points satisfying a given geometric condition. For a segment, the locus of points equidistant from both endpoints is its perpendicular bisector.

    PX = PY ⟺ P lies on the perpendicular bisector
    Angle Bisector

    A ray that divides an angle into two angles of equal measure.

    ∠BOC = ∠AOC = ½ ∠AOB
    Equilateral Triangle

    A triangle with all three sides of equal length and all three interior angles equal to 60°.

    a = b = c, ∠A = ∠B = ∠C = 60°
    Regular Hexagon

    A six-sided polygon with all six sides equal and all six interior angles equal to 120°.

    Interior angle = 120°, 6 equilateral triangles
    Rotational Symmetry

    The property of a figure that looks identical to itself after a rotation by an angle strictly less than 360°.

    Order n = 360° ÷ θ
    Śulba-Sūtras

    Ancient Indian Vedic geometric texts ('rules of the cord') describing altar constructions using ropes and pegs.

    Tiling (Tessellation)

    The covering of a flat plane or region using a collection of shapes with no gaps and no overlapping regions.

    Domino Tile

    A rectangular tile composed of two congruent unit squares joined edge-to-edge (size 2 × 1).

    Parity (Area Argument)

    The evenness or oddness of an integer. In domino tilings, since each tile covers 2 squares, the total area must be even.

    Area = 2k (must be even)
    Checkerboard Colouring Proof

    An impossibility proof technique where grid squares alternate black and white. Since each 2×1 domino covers 1 black and 1 white square, unequal counts ($B \ne W$) prove tiling is impossible.

    B = W is necessary for domino tiling
    Tangram

    An ancient Chinese geometric dissection puzzle formed by cutting a square into 7 geometric shapes.

    Trefoil Arch

    An architectural arch featuring three symmetrical circular lobes supported by equal line segments.

    Aperiodic Monotile ('The Hat')

    A single geometric tile discovered in 2023 that can tile the entire flat plane without ever repeating in a periodic pattern.

    Frequently Asked Questions (FAQ)

    What is a perpendicular bisector and how is it constructed?

    A perpendicular bisector is a straight line that divides a line segment into two equal halves at a 90° right angle. It is constructed using a compass by drawing two arcs of equal radius (greater than half the segment) from each endpoint above and below the segment, then joining their intersection points.

    Why does the perpendicular bisector pass through the midpoint?

    Every point on the perpendicular bisector is equidistant from the two endpoints. By triangle congruence (SSS on the outer triangles, followed by SAS on the half-triangles), the two segments formed on the line are proven equal in length (OX = OY) and the angles are equal straight-line supplementary angles (90° each).

    How do you construct a 90° angle at a point on a line?

    Mark two points X and Y at equal distances from the given point O using a compass, making O the midpoint of segment XY. Then construct the perpendicular bisector of XY. Since O is already on the bisector, you only need one pair of intersecting arcs above O, and joining that intersection to O gives the 90° angle.

    What were the Śulba-Sūtras and how did they construct perpendiculars?

    The Śulba-Sūtras are ancient Indian geometric treatises of the Vedic period that provided precise instructions for building fire altars. Instead of compasses, geometers used a rope with loops at the ends and a marked midpoint. By fastening the loops to pegs at endpoints X and Y and stretching the midpoint taut above and below, they created the perpendicular bisector.

    How do you bisect any given angle using a ruler and compass?

    Draw an arc centered at the vertex O cutting the two arms at points A and B (so OA = OB). From centres A and B, draw intersecting arcs of equal radius inside the angle to meet at point C. Ray OC bisects the angle into two equal parts because ΔOBC ≅ ΔOAC by SSS.

    How do you copy an angle to another location without measuring it?

    Draw an arc from the original vertex cutting the arms at two points. With the same compass radius, draw an arc at the new vertex. Measure the straight-line distance (chord) between the two arm intersections on the original angle with your compass, and transfer this length onto the new arc. Drawing a ray through the intersection reproduces the angle by SSS congruence.

    How can a 60° angle be constructed with ruler and compass?

    Draw an arc from vertex A cutting the baseline at B. Keeping the exact same compass radius, draw an arc from B intersecting the first arc at point C. Ray AC forms an equilateral triangle ΔABC with the baseline, so ∠CAB = 60°.

    How do you construct 30° and 15° angles?

    First construct a 60° angle using an equilateral triangle. Bisect the 60° angle to obtain two 30° angles. Bisecting a 30° angle yields a 15° angle.

    How do you construct a regular hexagon using an unmarked ruler and compass?

    A regular hexagon consists of six congruent equilateral triangles around a common central point. Construct a circle with radius equal to the desired side length. Step the compass around the circumference six times using the same radius to mark the six vertices, then connect adjacent vertices.

    What is the mathematical definition of tiling (tessellation)?

    Tiling is the complete covering of a region or flat plane using a set of shapes without any gaps (empty spaces) and without any overlapping boundaries.

    Why can't a 5 × 7 grid be tiled using 2 × 1 dominoes?

    A 5 × 7 grid contains 35 unit squares. Each 2 × 1 domino covers exactly 2 squares. Covering the board with dominoes would require 35 ÷ 2 = 17.5 dominoes, which is impossible because you cannot use half a domino. The area is odd, so tiling is impossible.

    How does checkerboard (black-and-white) colouring prove that some regions cannot be tiled?

    When a grid is colored like a checkerboard, every 2 × 1 domino must cover exactly one black square and one white square. If a region has unequal numbers of black and white squares (e.g. 8 white and 6 black), no domino tiling can ever exist.

    Which regular polygons can tile the entire flat plane on their own?

    Only three regular polygons can tile the Euclidean plane on their own: equilateral triangles (interior angle 60°, 6 meet at each vertex), squares (interior angle 90°, 4 meet at each vertex), and regular hexagons (interior angle 120°, 3 meet at each vertex). Their interior angles divide 360° evenly.

    Why do bees construct honeycombs with hexagonal cells?

    Regular hexagons tile the plane seamlessly without wasted space. Furthermore, among the three shapes that tile the plane (triangles, squares, hexagons), hexagons have the smallest perimeter for a given area, allowing bees to store the maximum honey while using the minimum amount of beeswax.

    What is an aperiodic monotile, and when was one discovered?

    An aperiodic monotile is a single geometric shape that can tile the entire plane without ever forming a repeating periodic pattern. Mathematicians searched for one for decades until 2023, when a shape nicknamed 'the hat' was discovered by an international team of mathematicians.

    Chapter Summary: What You Built & Discovered!

    A division of a line segment or geometrical quantity into two identical parts is called bisection.
    Any point equidistant from the endpoints of a segment lies on its perpendicular bisector.
    A 90° angle at any point on a line is constructed using the perpendicular bisector method.
    Angle bisection and angle copying are mathematically guaranteed by triangle congruence (SSS).
    A 60° angle is constructed using an equilateral triangle, and bisected to form 30° and 15°.
    Six congruent equilateral triangles around a point form a regular hexagon (6 × 60° = 360°).
    Parallel lines are constructed through an external point by copying corresponding angles.
    Tiling is covering a region using a set of shapes without gaps or overlaps.
    An m × n grid can be tiled by 2×1 dominoes if and only if at least one dimension is even.
    Checkerboard colouring proves tiling impossibility: each 2×1 domino covers 1 black and 1 white square.
    Only three regular polygons tile the Euclidean plane on their own: equilateral triangles, squares, and hexagons.
    🌟 Ganita Prakash Grade 7 Part-II Chapter 6 — Complete!
    You built geometry with a ruler and compass, justified every construction with triangle congruence, and unlocked the mathematical proofs of tilings!

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    Write down your observations on perpendicular bisectors, angle bisections, and checkerboard proofs. Saved automatically in your browser.

    Content strictly aligned with NCERT Ganita Prakash, Grade 7, Part-II, Chapter 6: Constructions and Tilings (Reprint 2026–27).